Like the picture
If there is [e] in the list, I want to delete [e].
When I press the delete button first, [e] disappears.
If I press the delete button after that, it disappears from the end of the list.
If I keep pressing the delete button, all the items in the list will be deleted.
What I want is
First I delete the [e] by pressing the delete button. And I press delete button afterwards. At this time, there is no [e] so it should not be deleted.
How can I implement this?
If an item in the list is not found, the search block returns 0, and the delete block from the list deletes the first item from the end. If you pass -1 to the delete block, the second element from the end will be deleted. I think you understand the algorithm of this block.
This is a bug of the system. The fact is that working with lists in Thunkable X is implemented artificially, not the way it works in programming languages.
guess what will be shown in the list if you specify Intex 0, 1 or -1
