This is such a simple question. I tried all possibilities but none of them worked. Doc:
Repeat an action the specified number of times
Count with i from [1] to [10] by [1]
https://x.thunkable.com/copy/c8cc556efd2ca92abd96d8823bc814ab
1, 1, 1 I expected the count loop not to enter but it entered once. When I tried -1 it entered 3 times. First it surprised me then I realized what it was doing. It was decrementing to -1. So if it is 1 to 1 by 1 technically it should not enter the loop at all. I am stuck here. Please help
Your blocks are:
Why are you trying to count from 1 to 1? That loop will happen one time. If you are trying negative numbers, please post a screenshot of those blocks.
Thanks for getting back to me. My question is I don’t want it to loop even once.
In this case if #j = 1 I dont want the inner count #i loop making any loops. It should get bypassed. For #j = 2 and above do the loop. Ofcourse I can put a if block and solve the issue. However I want to avoid putting the if block, if count has the capability to skip then that would be ideal. In C++ this is possible.
I understand that you’re wanting to re-create loops from C++. I’m maybe not the best person to help you with this because I don’t do a lot of coding outside of Thunkable. I do understand a basic C++ loop. I just don’t have a lot of experience implementing them.
But I’m curious… is this for a sort or recursion of some other method that requires a loop from 1 to 1 by 1 to not fire at all?
